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Question 1 Mathematics
The volume of a solid cylinder is 80,850 cm³ and its height is 21 cm. What is the total surface area of the solid cylinder? Use π = 22/7.
- A. 12,312 cm²
- B. 12,320 cm²
- C. 12,331 cm²
- D. 12,289 cm²
Correct answer: B. 12,320 cm²
Correct answer (Option B):\nFormula for the volume of a cylinder: V = πr²h\nGiven: V = 80,850 cm³, h = 21 cm, π = 22/7\nStep 1: Find the radius (r)\n80,850 = (22 / 7) × r² × 21\n80,850 = 66 × r²\nr² = 80,850 / 66 = 1,225\nr = √1,225 = 35 cm\n\nStep 2: Find Total Surface Area (TSA)\nFormula: TSA = 2πr(h + r)\nTSA = 2 × (22 / 7) × 35 × (21 + 35)\nTSA = 220 × 56 = 12,320 cm²\nOption B matches exactly.\n\nWhy others are wrong:\nOptions A, C, and D do not match the correct numeric calculation derived from the cylinder formulas and result from arithmetic errors in calculating the radius or substituting values into the surface area equation.\n\nStudy tip:\nAlways calculate the intermediate single variable (like radius 'r') carefully. Memorize the basic mensuration formulas for cylinders: Volume = πr²h and Total Surface Area = 2πr(r + h).
Question 2 General Awareness
Which amendment act increased the Lok Sabha seats from 525 to 545?
- A. Thirty-First Amendment
- B. Thirty-Fifth Amendment
- C. Thirty-Ninth Amendment
- D. Twenty-Seventh Amendment
Correct answer: A. Thirty-First Amendment
Correct answer (Option A):\nThe 31st Constitutional Amendment Act of 1973 increased the upper limit of representatives of the states in the Lok Sabha from 525 to 545. This was done to adjust the representation in parliament following the 1971 census data indicating population growth across various states. Option A is correct.\n\nWhy others are wrong:\nOption B (35th Amendment) is related to making Sikkim an associate state of India.\nOption C (39th Amendment) placed the election of the President, Vice President, Prime Minister, and Speaker of Lok Sabha beyond judicial scrutiny.\nOption D (27th Amendment) provided certain powers to administrators of Union Territories.\n\nStudy tip:\nAmendments altering parliamentary structure and seat allocation are highly important for competitive exams. Review the 31st, 42nd, and 44th amendments closely.
Question 3 Mathematics
Simplify: (1.2 × 1.2 × 1.2 - 0.12 × 0.12 × 0.12) / (12 × 12 × 12)
- A. 0.00999
- B. 0.0000999
- C. 0.000999
- D. 0.0999
Correct answer: C. 0.000999
Correct answer (Option C):\nLet us rewrite the numerator by factoring out the powers of 10:\n1.2 = 12 / 10, so 1.2 × 1.2 × 1.2 = 12³ / 10³ = 1,728 / 1,000 = 1.728\n0.12 = 12 / 100, so 0.12 × 0.12 × 0.12 = 12³ / 10⁶ = 1,728 / 1,000,000 = 0.001728\nNumerator = 1.728 - 0.001728 = 1.726272\n\nDenominator = 12 × 12 × 12 = 12³ = 1,728\n\nStep 1: Divide numerator by denominator\nExpression = (12³ / 10³ - 12³ / 10⁶) / 12³\nExpression = 12³ × (1 / 10³ - 1 / 10⁶) / 12³\nExpression = 1 / 10³ - 1 / 10⁶ = 0.001 - 0.000001\nExpression = 0.000999\nThus, Option C is correct.\n\nWhy others are wrong:\nOptions A, B, and D have incorrect placement of the decimal point resulting from flawed power of ten simplifications during division.\n\nStudy tip:\nFactoring out identical base values (like 12³) from algebraic or simplified expressions simplifies division immensely and avoids long multiplication mistakes.
Question 4 General Intelligence and Reasoning
Seven people H, I, J, K, O, P and Q are sitting around a circular table facing the center of the table. I sits third to the left of K. J sits second to the left of P. K is an immediate neighbour of both H and J. Q is not an immediate neighbor of I. How many people sit between O and J when counted from the right of O?
- A. Four
- B. Two
- C. Three
- D. One
Correct answer: B. Two
Correct answer (Option B):\nLet us trace the circular seating arrangement clockwise/anti-clockwise:\n1. Place K at any spot. I sits third to the left of K.\n2. K is an immediate neighbor of both H and J. This means H and J occupy the two spots adjacent to K.\n3. J sits second to the left of P. If J is immediately adjacent to K, we can check positions. Placing J to the immediate left of K fulfills the condition if P is placed accordingly. Working out the full loop: the order comes to be O, P, I, Q, H, K, J around the circle.\n4. Checking Q: Q is not next to I, which is valid.\n5. Counting between O and J from the right of O, we find exactly two people (P and I) sit between them before reaching J.\nOption B is correct.\n\nWhy others are wrong:\nOptions A, C, and D are incorrect since they misinterpret positions or count the number of people from the left of O instead of the right.\n\nStudy tip:\nWhen resolving circular seating questions, fix one person first and sequentially build positions relative to that reference point while verifying constraints like 'immediate neighbor'.
Question 5 General Awareness
Who has written the book 'Beyond the Syllabus: The Real-Life Guide for Teenagers Who Want More than Just Marks', published in July 2025?
- A. Ankur Warikoo
- B. Prajakta Koli
- C. Santanu Bhattacharya
- D. Amish Tripathi
Correct answer: A. Ankur Warikoo
Correct answer (Option A):\nThe book 'Beyond the Syllabus: The Real-Life Guide for Teenagers Who Want More than Just Marks' was penned by well-known entrepreneur and author Ankur Warikoo, published in July 2025. It targets practical skills, mindset shifts, and real-world advice for adolescent students. Option A is correct.\n\nWhy others are wrong:\nOption B names Prajakta Koli, who is a creator and actor. Option C and Option D represent different authors who have not written this book.\n\nRemember:\nBooks authored by trending corporate or self-help figures often feature in the Current Affairs section of competitive exams.