SSC CGL T-I Similar Paper (Held on 12 Sep 2025 S2) — Kerala PSC PYQ Practice with Answers

Part 1 — Correct answer (Option B):\nLet the two numbers be 5x and 7x. According to the problem statement, their sum is 144. Therefore, we can set up the linear equation: 5x + 7x = 144. Simplifying this gives 12x = 144, which means x = 12. Substituting x back into our expressions for the numbers, the first number is 5 × 12 = 60 and the second number is 7 × 12 = 84. Thus, the numbers are 60 and 84, matching Option B perfectly.\n\nPart 2 — Why others are wrong:\nOption A (50, 94) is incorrect because the ratio 50:94 simplifies to 25:47, not 5:7. Option C (55, 89) breaks the required 5:7 ratio completely. Option D (65, 79) also does not form the correct ratio, though all these options sum up to 144.\n\nPart 3 — Study tip:\nIn ratio and proportion questions, always define components using a common variable x. For quick checking in SSC exams, verify both the sum and the ratio directly from the choices.

Part 1 — Correct answer (Option B):\nLet us examine the differences between successive terms in the series: 249 - 249 is the last term. The difference between 249 and 204 is 45. The difference between 204 and 165 is 39. The difference between 165 and 132 is 33. Notice the differences themselves form a pattern: 45, 39, 33, which decrease by 6 each time. Continuing this backwards, the previous difference must be 33 - 6 = 27. Therefore, the missing first term is 132 - 27 = 105. This confirms Option B is correct.\n\nPart 2 — Why others are wrong:\nOption A (96) assumes a wrong step reduction. Option C (108) means the initial difference would be 24, breaking the arithmetic progression of differences. Option D (120) yields a difference of 12, which fails the steady decreasing pattern of 6.\n\nPart 3 — Study tip:\nThis is a nested series or "difference of differences" problem. When primary differences don't immediately form an obvious constant sequence, compute the second tier of differences to find patterns.

Part 1 — Correct answer (Option B):\nFirst, we sort the letters of the 11-letter word COMPETITION alphabetically: C, E, I, I, M, N, O, P, T, T, T. The 1st letter from the left in this sorted sequence is 'C'. The 2nd letter from the right end is 'T' (the last three are T, T, T). We need to find how many letters lie strictly between this 'C' and this 'T'. The full sequence of letters between them is E, I, I, M, N, O, P, T. Counting these letters gives exactly 8 letters. Hence, Option B is correct.\n\nPart 2 — Why others are wrong:\nOption A (9) overcounts by including one of the outer anchoring positions. Option C (10) represents an incorrect count of the remaining internal letter spaces. Option D (6) significantly undercounts the internal letter sequence by missing the repeated elements.\n\nPart 3 — Study tip:\nBe careful with duplicates when rearranging words alphabetically. Always count total letters before and after sorting to make sure no letters are missed.

Part 1 — Correct answer (Option A):\nLet us trace the family relationship step by step. We are given that X is the daughter of Y, which makes Y the parent of X (specifically the father, since the next clue tells us his gender). We are also told that Y is the brother of Z. This means Z is the sibling of X's father Y. The daughter of one's brother is defined as a niece. Therefore, X is the niece of Z, making Option A the correct choice.\n\nPart 2 — Why others are wrong:\nOption B (Daughter) is incorrect because X is the daughter of Y, not Z. Option C (Sister) is wrong because X belongs to a generation below Z. Option D (Cousin) is wrong because cousins belong to the same generation, whereas X is a niece.\n\nPart 3 — Study tip:\nWhen drawing family trees for blood relations, use horizontal lines for siblings, vertical lines for generations, and assign clear plus/minus symbols for genders to avoid confusion.

Part 1 — Correct answer (Option B):\nLet us analyze the relationship between the base word NUMBER and its coded form ERBMUN. Writing the word NUMBER in exact reverse order gives: N→R, U→E, etc., which spells out E-R-B-M-U-N. The pattern is simply reversing the entire string. Applying this identical rule to the target word SCHOOL: reversing the letters from right to left gives S-C-H-O-O-L in reverse, which is O-L-O-H-C-S. This matches Option B.\n\nPart 2 — Why others are wrong:\nOption A (LHCOSO) scrambles the letters using a completely different transposition. Option C (OLHOSC) misses the correct placement of middle letters. Option D (LOOCHS) incorrectly leaves parts of the word unreversed or jumbled up.\n\nPart 3 — Study tip:\nString reversal is one of the most basic coding-decoding patterns in SSC Reasoning. Always look at the first and last letters of the coded example first to detect a simple mirror swap.