SSC CGL — Tier 1 — 2025 — 15 Sep 2025 (Shift II) — Official Paper — Kerala PSC PYQ Practice with Answers

Correct answer (Option D):\nLet us decode the mathematical operator logic used in the problem.\n\nFirst expression:\n6 * 4 = 40\nPattern evaluation: (6 × 4) + (4 × 4) = 24 + 16 = 40\nAlternatively, consider: 4 × (6 + 4) = 4 × 10 = 40\n\nSecond expression:\n8 * 3 = 33\nPattern evaluation: 3 × (8 + 3) = 3 × 11 = 33\n\nThe established mathematical rule for the operation is: A * B = B × (A + B)\n\nApplying this rule to the target values where A = 5 and B = 6:\nStep 1: A + B = 5 + 6 = 11\nStep 2: B × (A + B) = 6 × 11 = 66\n\nFinal computed value is 66. Option D matches this result.\n\nWhy others are wrong:\nOption A (64), Option B (70), and Option C (68) do not comply with the consistent algebraic pattern discovered across both reference configurations.\n\nStudy tip:\nMathematical operations in reasoning sections frequently replace custom placeholders with standard structural formulas like B × (A + B) or A² - B. Work with the smaller multiplier first to verify variables rapidly.

Correct answer (Option B):\nLet us look at the positional offsets between the source word 'SCHOOL' and its encrypted form 'XHMTTQ':\nS → X (Position 19 to 24: +5)\nC → H (Position 3 to 8: +5)\nH → M (Position 8 to 13: +5)\nO → T (Position 15 to 20: +5)\nO → T (Position 15 to 20: +5)\nL → Q (Position 12 to 17: +5)\n\nThe rule requires shifting every alphabet forward by exactly +5 steps.\n\nApplying this system to 'TEACHER':\nT (+5) = Y\nE (+5) = J\nA (+5) = F\nC (+5) = H\nH (+5) = M\nE (+5) = J\nR (+5) = W\n\nCombining the generated characters yields 'YJFHMJW'. Therefore, Option B is correct.\n\nWhy others are wrong:\nOption A begins with 'W' due to a tracking error. Option C uses 'I' and 'X' which violates the fixed shift logic. Option D provides an inaccurate character chain near the center index.\n\nStudy tip:\nWrite out positional values (A=1, Z=26) immediately when processing alphabet patterns. Verifying the first two and the final letter of a code word can quickly isolate the correct choice among option sets.

Correct answer (Option D):\nThis question requires checking structural uniformity across strings including spaces, hyphens, and numeric characters to locate an identical match for: 'A-27, Green Valley, Sector-5, Noida, Uttar Pradesh - 201301'.\n\nLet us evaluate each option line by line:\nOption D features complete synchronization with all commas, internal spaces, exact hyphens, and the correct postal code arrangement.\n\nWhy others are wrong:\nOption A changes 'Sector-5' to 'Sector 5' by removing the required hyphen.\nOption B modifies the last digits of the PIN code from '201301' to '201310'.\nOption C omits the punctuation comma after the phrase 'Green Valley'.\n\nStudy tip:\nTreat address-matching questions as high-speed identity drills. Inspect characters from right to left (starting with pin codes and punctuation marks) to exclude incorrect options efficiently.

Correct answer (Option A):\nLet us trace the alphabet grouping progression to evaluate the missing entry:\nFirst group: m, n\nSecond group: o, p\n\nNotice that the pairs are composed of consecutive letters in standard alphabetical order with no missing letters between the groups: m, n → o, p.\nFollowing this continuous chain, the next pair of consecutive letters after 'p' must be 'q, r'.\n\nVerifying with the rest of the sequence:\nAfter 'qr' comes 's, t', followed by 'u, v'. The chain functions perfectly without any gaps.\nHence, Option A is correct.\n\nWhy others are wrong:\nOption B (pq) duplicates previous segments. Option C (rs) skips the letter q entirely. Option D (tu) matches the group positioned later in the sequence.\n\nStudy tip:\nAlphabet series can be continuous or involve skipping steps. Map out the sequence dynamically to determine if the pattern relies on uniform groupings or incrementing gaps.

Correct answer (Option B):\nTo sort the words according to standard dictionary order, we evaluate them character by character from left to right:\nAll words begin with the letter 'a'. Let us evaluate the second character:\n- ant: 'n'\n- ape: 'p'\n- apple: 'p'\n- april: 'p'\n\nSince 'n' comes before 'p', 'ant' is the first word in the sorted arrangement.\n\nNow we compare the remaining words (ape, apple, april) starting from their third character:\n- ape: third slot is empty (terminates first)\n- apple: 'p'\n- april: 'r'\n\nComparing these tells us that 'ape' comes before 'apple', and 'apple' comes before 'april'.\n\nThe complete ordered list is: 1. ant, 2. ape, 3. apple, 4. april.\nThe second word in this sequence is 'ape'. Option B is correct.\n\nWhy others are wrong:\nOption A (ant) represents the first item in order. Option C (apple) is the third entry, and Option D (april) is the fourth entry.\n\nStudy tip:\nWhen sorting words with identical starting paths, the shorter word whose characters end first always takes precedence in dictionary ordering.