SSC CGL — Tier 1 — 16 Sep 2025 — Shift III — Official Paper — Kerala PSC PYQ Practice with Answers

Browse preview questions from SSC CGL — Tier 1 — 16 Sep 2025 — Shift III — Official Paper. Sign in for timed full-paper practice in the app.

Tier 1CGL2025English

Paper details

  • Paper code: ssc-cgl-tier-1-2025-09-16-s3
  • Format: Full previous year paper — PYQ practice with answers

How to open this paper in PSC PYQ

Open the app and navigate: Exam Browse → SSC CGL — Tier 1 — 16 Sep 2025 — Shift III — Official Paper.

Attempt the full paper under timed conditions, then review weak topics using the preview links below or topic-wise practice in the app.

Preview questions (5)

Sample PYQs from this paper with answers and explanations — sign in for the full paper in the app.

Question 1 Reasoning
If + = -, - = ×, × = + evaluate:\n6 + 3 × 2 - 4?
  1. A. 14
  2. B. 16
  3. C. 18
  4. D. 11

Correct answer: D. 11

Correct answer (Option D):\nAccording to the problem, the mathematical signs are substituted as follows:\n+ becomes -\n- becomes ×\n× becomes +\n\nLet us substitute these operators into the given expression:\nOriginal expression: 6 + 3 × 2 - 4\nNew expression: 6 - 3 + 2 × 4\n\nNow, applying the BODMAS rule, perform multiplication first:\nStep 1: 2 × 4 = 8\nExpression becomes: 6 - 3 + 8\n\nStep 2: Perform addition and subtraction from left to right:\n6 - 3 = 3\n3 + 8 = 11\n\nFinal computed answer is 11, which matches Option D.\nOption D is correct.\n\nWhy others are wrong:\nOption A results from evaluating without changing the minus sign to multiplication. Option B comes from evaluating the steps in a wrong chronological sequence. Option C happens if you add 3 and 8 first but accidentally switch or miscalculate signs.\n\nStudy tip:\nAlways rewrite the expression explicitly with the new signs before doing any math. Follow the BODMAS rule strictly to determine the correct hierarchy of operations.
Question 2 Reasoning
If 5 @ 2 = 25, 4 @ 3 = 64, then 3 @ 4 = ?
  1. A. 81
  2. B. 64
  3. C. 48
  4. D. 12

Correct answer: A. 81

Correct answer (Option A):\nLet us identify the pattern or mathematical operation represented by the symbol @.\nGiven logic:\n5 @ 2 = 25 → 5² = 25\n4 @ 3 = 64 → 4³ = 64\n\nThe operation takes the number before the @ as the base and the number after the @ as the exponent:\nPattern: x @ y = x^y\n\nApplying this pattern to the query 3 @ 4:\n3 @ 4 = 3⁴\nCalculation step: 3 × 3 × 3 × 3 = 81\n\nTherefore, the computed value is 81.\nOption A is correct.\n\nWhy others are wrong:\nOption B (64) is incorrect because it represents 4³, which is the previous term pattern rather than 3⁴. Option C (48) results from multiplying 3 by 16 or an unrelated sequence error. Option D (12) simply multiplies the base and exponent (3 × 4 = 12), failing to apply the exponential relationship.\n\nStudy tip:\nWhen encountering arbitrary symbols in reasoning, test if they represent standard mathematical relationships like addition, multiplication, or powers. Checking multiple examples verifies the theory.
Question 3 Reasoning
Select the correct letter-cluster to replace (?).\nAAEI, BFJN, CGOS, DHTX, ?
  1. A. EIQC
  2. B. EIQZ
  3. C. EIYC
  4. D. EJQZ

Correct answer: C. EIYC

Correct answer (Option C):\nLet us analyze the position shift for each corresponding letter in the series:\n\n1st Letter: A → B → C → D → ? (+1 shift)\nD + 1 = E\n\n2nd Letter: A → F → G → H → ? \nLooking at the sequence printed in the paper: A, F, G, H seems to shift from F (+1) onwards. Let us evaluate alphabetical indices: \nIf it tracks A (+5) → F (+1) → G (+1) → H (+1) → I. So the next second letter is I.\n\n3rd Letter: E → J → O → T → ? (+5 shift)\nE(5) + 5 = J(10)\nJ(10) + 5 = O(15)\nO(15) + 5 = T(20)\nT(20) + 5 = Y(25). Third letter is Y.\n\n4th Letter: I → N → S → X → ? (+5 shift)\nI(9) + 5 = N(14)\nN(14) + 5 = S(19)\nS(19) + 5 = X(24)\nX(24) + 5 = 29 → 29 - 26 = C(3). Fourth letter is C.\n\nCombining the terms gives EIYC.\nOption C is correct.\n\nWhy others are wrong:\nOption A (EIQC) uses Q instead of Y as the third letter, breaking the constant +5 alphabetical gap. Option B (EIQZ) uses incorrect letters for both final spots. Option D (EJQZ) misses the correct progression rule across multiple character indices.\n\nStudy tip:\nBreak down multi-letter series into individual linear tracks. Write out numerical positions (A=1, B=2...) to quickly discover incremental intervals.
Question 4 Reasoning
Complete the analogy:\nBDGK: YWTP :: CEHL:?
  1. A. XVSK
  2. B. XVSO
  3. C. XWSL
  4. D. XWTL

Correct answer: B. XVSO

Correct answer (Option B):\nThe analogy utilizes pairs of reverse or opposite letters in the alphabet where the sum of their positions is 27.\n\nLet us evaluate the first pair BDGK : YWTP\nB (2) ↔ Y (25) -> 2 + 25 = 27\nD (4) ↔ W (23) -> 4 + 23 = 27\nG (7) ↔ T (20) -> 7 + 20 = 27\nK (11) ↔ P (16) -> 11 + 16 = 27\n\nNow, let us find the corresponding reverse letters for CEHL:\nC (3) ↔ X (24) -> 3 + 24 = 27\nE (5) ↔ V (22) -> 5 + 22 = 27\nH (8) ↔ S (19) -> 8 + 19 = 27\nL (12) ↔ O (15) -> 12 + 15 = 27\n\nPutting these together gives XVSO.\nOption B is correct.\n\nWhy others are wrong:\nOption A (XVSK) uses K instead of O at the end, which is the original letter K reversed rather than the opposite of L. Option C (XWSL) maps E to W and leaves L unchanged, violating the reverse pair rule. Option D (XWTL) similarly fails to apply opposites for the intermediate elements.\n\nStudy tip:\nMemorize standard opposite pairs (A-Z, B-Y, C-X, etc.). A quick validation is verifying that the alphabetical rank from the start equals the rank from the end.
Question 5 Reasoning
Choose the address that is exactly the same as the one given below.\nB-45, Green Park Extension, New Delhi, Delhi - 110016
  1. A. B-45, Green Park Extention, New Delhi, Delhi - 110016
  2. B. B-45, Green Park Extension, New Delli, Delhi - 110016
  3. C. B-45, Green Park Extension, New Delhi, Delhi - 110061
  4. D. B-45, Green Park Extension, New Delhi, Delhi - 110016

Correct answer: D. B-45, Green Park Extension, New Delhi, Delhi - 110016

Correct answer (Option D):\nThis is an address matching question requiring precise comparison of each word, spelling, character, and digit.\n\nLet us verify option D:\n'B-45, Green Park Extension, New Delhi, Delhi - 110016' matches the source text exactly token for token.\nOption D is correct.\n\nWhy others are wrong:\nOption A contains a spelling mistake: 'Extention' instead of 'Extension'.\nOption B contains a typo: 'New Delli' instead of 'New Delhi'.\nOption C alters the pincode digits to '110061' instead of '110016'.\n\nStudy tip:\nIn verification questions, scan the text chunk by chunk, focusing closely on numeric digits, endings (-tion vs -sion), and punctuation marks.

Frequently asked questions

Browse preview questions on this page, or sign in at https://pscpyq.online/app/ and open the same paper in Exam Browse.
Sign in at PSC PYQ to practice the complete previous year paper with all questions and explanations.

Ready to secure your government job?

Start SSC CGL — Tier 1 — 16 Sep 2025 — Shift III — Official Paper PYQ practice with instant answers and progress tracking.