SSC CGL — Tier 1 — 2025 — 17 Sep 2025 — Shift I — Sample Paper — Kerala PSC PYQ Practice with Answers

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Tier 1CGL2025English

Paper details

  • Paper code: ssc-cgl-tier-1-2025-17-sep-s1
  • Format: Full previous year paper — PYQ practice with answers

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Preview questions (5)

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Question 1 Reasoning
P is the sister of Q. R is the father of Q. How is R related to P?
  1. A. Father
  2. B. Uncle
  3. C. Brother
  4. D. Grandfather

Correct answer: A. Father

Correct answer (Option A):\nSince P is the sister of Q, P and Q are siblings. R is the father of Q, which means R must also be the father of P.\nOption A is correct.\n\nWhy others are wrong:\nOption B is incorrect because R is the direct parent, not an uncle.\nOption C is incorrect because R belongs to the previous generation.\nOption D is incorrect because R is the immediate father, not a grandfather.\n\nStudy tip:\nIn blood relation problems, draw a family tree with horizontal lines for siblings and vertical lines for generations to clearly visualize relationships.
Question 2 Reasoning
Find the odd one out:
  1. A. Copper
  2. B. Iron
  3. C. Gold
  4. D. Plastic

Correct answer: D. Plastic

Correct answer (Option D):\nCopper, Iron, and Gold are all metallic elements and good conductors of electricity and heat. Plastic is a synthetic polymer and a non-metal insulator.\nOption D is correct.\n\nWhy others are wrong:\nOptions A, B, and C are incorrect because they form a homogeneous group of metallic elements.\n\nStudy tip:\nClassification questions require identifying a common property shared by three options which is completely missing in the odd option.
Question 3 Quantitative Aptitude
A 20 L mixture contains milk and water in the ratio 2:3. How much milk must be added to make the ratio 4:3?
  1. A. 10 L
  2. B. 8 L
  3. C. 5 L
  4. D. 9 L

Correct answer: B. 8 L

Correct answer (Option B):\nGiven total volume = 20 L\nInitial ratio of milk to water = 2:3\nTotal units = 2 + 3 = 5 units\nValue of 1 unit = 20 / 5 = 4 L\nInitial quantity of milk = 2 × 4 = 8 L\nInitial quantity of water = 3 × 4 = 12 L\n\nWe want the new ratio of milk to water to be 4:3.\nSince only milk is added, the quantity of water remains unchanged at 12 L.\nIn the new ratio, 3 units of water = 12 L\nNew value of 1 unit = 12 / 3 = 4 L\nNew quantity of milk required = 4 × 4 = 16 L\n\nMilk to be added = New milk - Initial milk\nMilk to be added = 16 L - 8 L = 8 L\nOption B is correct.\n\nWhy others are wrong:\nOptions A, C, and D do not satisfy the required final ratio of 4:3 when added to the original 8 L of milk.\n\nStudy tip:\nWhen working with mixtures where only one component changes, keep the quantity of the other component constant across your ratio calculations.
Question 4 Reasoning
If + means ×, - means ÷, × means +, and ÷ means -, then find the value of:\n24 + 6 - 2 × 4 ÷ 2 = ?
  1. A. 76
  2. B. 72
  3. C. 78
  4. D. 74

Correct answer: D. 74

Correct answer (Option D):\nSubstitute the signs as per the given instructions:\n+ becomes ×\n- becomes ÷\n× becomes +\n÷ becomes -\n\nOriginal expression: 24 + 6 - 2 × 4 ÷ 2\nNew expression: 24 × 6 ÷ 2 + 4 - 2\n\nApply BODMAS rules step-by-step:\nStep 1 (Division): 6 ÷ 2 = 3\nExpression becomes: 24 × 3 + 4 - 2\nStep 2 (Multiplication): 24 × 3 = 72\nExpression becomes: 72 + 4 - 2\nStep 3 (Addition): 72 + 4 = 76\nExpression becomes: 76 - 2\nStep 4 (Subtraction): 76 - 2 = 74\nOption D is correct.\n\nWhy others are wrong:\nOptions A, B, and C are calculated by ignoring the correct operator hierarchy or misinterpreting the sign substitutions.\n\nStudy tip:\nAlways rewrite the entire expression clearly after substituting signs before performing any calculations under BODMAS.
Question 5 Reasoning
Select the letter-cluster from among the given options that can replace the question mark (?) in the following series:\nCFG, EHI, GJK, ILM, ?
  1. A. KNO
  2. B. JMN
  3. C. JMO
  4. D. KMN

Correct answer: A. KNO

Correct answer (Option A):\nAnalyze the pattern for each position in the letter clusters:\n1st letter: C (+2) -> E (+2) -> G (+2) -> I (+2) -> K\n2nd letter: F (+2) -> H (+2) -> J (+2) -> L (+2) -> N\n3rd letter: G (+2) -> I (+2) -> K (+2) -> M (+2) -> O\nCombining the terms gives KNO.\nOption A is correct.\n\nWhy others are wrong:\nOptions B and C start with J, which breaks the first letter pattern.\nOption D contains M as the second letter, which fails the +2 shift sequence from L.\n\nStudy tip:\nWrite positional values (A=1, B=2, etc.) to quickly solve letter series questions.

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