SSC CGL — Tier 1 — 2025 — 17 Sep 2025 — Shift III — Previous Year Paper — Kerala PSC PYQ Practice with Answers

Correct answer (Option A):\nLet's examine the positional values of the alphabet letters in the given analogy:\nC = 3, D = 4\nO = 15, P = 16\nThe relation between C and O is: 3 + 12 = 15\nThe relation between D and P is: 4 + 12 = 16\nSo, the pattern is to add 12 to the positional values of each letter.\nApplying the same pattern to GH:\nG = 7, H = 8\nG + 12 = 7 + 12 = 19 (S)\nH + 12 = 8 + 12 = 20 (T)\nTherefore, GH relates to ST.\nOption A is correct.\n\nWhy others are wrong:\nOption B (UV) adds 14 to the positions instead of 12.\nOption C (QR) adds 10 to the positions instead of 12.\nOption D (WX) adds 16 to the positions instead of 12.\n\nStudy tip:\nAlways quickly write down or recall the A = 1 to Z = 26 numbering scheme to easily compute differences in letter-shift clusters.

Correct answer (Option A):\nConclusion I directly follows because an increase in highway toll charges dynamically impacts the total expenditure required to travel on those roads, thus increasing the cost of road travel. Conclusion II uses an extreme condition by stating that people will 'completely stop' using highways, which is practically unrealistic and structurally unprovable from the given statement.\nOption A is correct.\n\nWhy others are wrong:\nOption B is wrong because Conclusion II uses an absolute or extreme assumption that cannot be derived from a baseline price hike.\nOption C is incorrect since both cannot follow given the logical flaw in II.\nOption D is incorrect because Conclusion I is a direct and valid outcome.\n\nStudy tip:\nIn statement-conclusion questions, avoid choosing conclusions that contain extreme words like 'completely', 'always', 'never', or 'all' unless explicitly supported by the premise.

Correct answer (Option A):\nLet's analyze the coding pattern for PLANE → QMBOF:\nP + 1 = Q\nL + 1 = M\nA + 1 = B\nN + 1 = O\nE + 1 = F\nThe pattern is a sequential +1 shift for every letter.\nApplying this same coding scheme to TRAIN:\nT + 1 = U\nR + 1 = S\nA + 1 = B\nI + 1 = J\nN + 1 = O\nThus, TRAIN is coded as USBJO.\nOption A is correct.\n\nWhy others are wrong:\nOption B (USBJM) applies a -1 shift to the final letter instead of +1.\nOption C (USBOJ) swaps the placement order of the last two letters.\nOption D (TSBOJ) fails to increment the first letter T.\n\nStudy tip:\nVerify every letter of your output string against all choices, as distractors are frequently engineered with mistakes located only in the terminal positions.

Correct answer (Option B):\nLet's trace the positional pattern of each letter cluster in the series:\n1st cluster: LMN\n2nd cluster: MNO (Each letter is shifted by +1 relative to the previous cluster's starting point, or it simply begins with the second letter of the preceding cluster)\n3rd cluster: NOP\n4th cluster: OPQ\nFollowing this consecutive alphabetical arrangement, the cluster directly following OPQ must start with P, giving PQR.\nOption B is correct.\n\nWhy others are wrong:\nOption A (QRS) skips the letter P entirely, moving ahead prematurely.\nOption C (LMN) simply duplicates the first element of the series.\nOption D (RST) jumps forward too many positions in the alphabet sequence.\n\nStudy tip:\nSeries based on triplets often reveal themselves by tracking the sequence of only the first character of each group.

Correct answer (Option B):\nFormula: Speed = Distance / Time\nGiven:\nDistance = 240 m\nTime = 12 seconds\nStep 1: Compute speed in meters per second (m/s):\nSpeed = 240 / 12 = 20 m/s\nStep 2: Convert speed to kilometers per hour (km/h) by multiplying by 18/5:\nSpeed = 20 × (18 / 5)\nSpeed = 4 × 18 = 72 km/h\nTherefore, the speed of the car is 72 km/h.\nOption B is correct.\n\nWhy others are wrong:\nOption A (60 km/h) happens if you use a multiplier of 3 instead of 18/5.\nOption C (54 km/h) is the result of 15 m/s, which implies a miscalculation of distance divided by time.\nOption D (48 km/h) is derived from a faulty metric conversion process.\n\nStudy tip:\nRemember the rapid conversion factors:\nTo convert m/s to km/h, multiply by 18/5.\nTo convert km/h to m/s, multiply by 5/18.