Junior Engineer Civil Paper I — 2024 — 07 Jun 2024 — Shift I — Official Paper — Kerala PSC PYQ Practice with Answers

Correct answer (Option C):\nThe original equation is: 82 + 52 ÷ 26 × 13 - 4 = ?\nAccording to the problem, we need to interchange the mathematical operators as follows:\n'+' becomes '-' and vice versa.\n'×' becomes '÷' and vice versa.\n\nSubstituting these changes into the original equation step-by-step:\nStep 1: Replace '+' with '-' and '-' with '+'\nStep 2: Replace '÷' with '×' and '×' with '÷'\nNew expression: 82 - 52 × 26 ÷ 13 + 4 = ?\n\nNow, applying the BODMAS rule (Bracket, Of, Division, Multiplication, Addition, Subtraction):\nStep 3 (Division): 26 ÷ 13 = 2\nExpression simplifies to: 82 - 52 × 2 + 4\nStep 4 (Multiplication): 52 × 2 = 104\nExpression simplifies to: 82 - 104 + 4\nStep 5 (Addition and Subtraction): 82 + 4 = 86\n86 - 104 = -18\n\nTherefore, the calculated value is -18.\n\nWhy others are wrong:\nOption A (36) is incorrect due to a calculation error or wrong operator substitution sequence.\nOption B (9) fails to correctly follow the division and negative sign rules.\nOption D (-68) results from mixing up the multi-step priorities under the BODMAS convention.\n\nStudy tip:\nAlways rewrite the operator map explicitly on your rough worksheet before solving to ensure no substitution errors are committed under time constraints.

Correct answer (Option B):\nLet us evaluate the statements using standard logical deduction or Venn diagrams:\nFrom the given statements:\n1. All kites belong inside the set of rocks.\n2. All rocks belong inside the set of lakes.\n3. All lakes belong inside the set of planets.\n\nEvaluating Conclusion I: 'All rocks are planets.' Since all rocks are inside lakes, and all lakes are inside planets, it follows transitively that all rocks are definitively inside planets. Thus, Conclusion I is true.\n\nEvaluating Conclusion II: 'At least some lakes are kites.' Since all kites are inside rocks and all rocks are inside lakes, the set of kites is entirely contained within lakes. This implies that there is a mutual intersection, meaning at least some parts of lakes are definitely occupied by kites. Thus, Conclusion II is also true.\n\nSince both conclusions follow logically, Option B is the correct choice.\n\nWhy others are wrong:\nOption A is incorrect because it neglects the absolute validity of Conclusion II.\nOption C is wrong because both statements have valid logical paths and are not contradictory.\nOption D is incorrect because it completely misses the validity of Conclusion I derived through nesting transitions.\n\nStudy tip:\nWhen all statements are affirmative and universal (using 'All'), structural containment transitions naturally hold from inside out.

Correct answer (Option B):\nLet us analyze the letter-rearrangement pattern used in the code language:\nFor 'DEFAULT' (7 letters):\nPositions: D(1) E(2) F(3) A(4) U(5) L(6) T(7)\nCode: D T L U A F E\nNotice the transformation:\n- The first letter 'D' stays at its original place (Position 1).\n- The remaining letters 'EFAULT' are completely reversed to become 'TLUAFE'.\n\nLet us verify this with 'BROUGHT' (7 letters):\nPositions: B(1) R(2) O(3) U(4) G(5) H(6) T(7)\nCode: B T H G U O R\n- The first letter 'B' stays at position 1.\n- The remaining letters 'ROUGHT' are completely reversed to form 'THGUOR'.\n\nApplying this identical pattern to 'FANTASY':\n- The first letter 'F' remains unchanged at the beginning.\n- The remaining letters 'ANTASY' must be completely reversed: Y -> S -> A -> T -> N -> A.\n- Combining them gives: FYSATNA.\n\nWait, let us re-verify the option chosen in the official key. The official layout reveals Option 3 is FYSATNA, but let us look closely at the choices.\nAh, let us re-examine the text content. Option 3 is marked as correct in the text metadata.\nLet us read Option 3: 'FYSATNA'. Let us align it with our pattern: F + reverse(ANTASY) = FYSATNA. This matches perfectly with Option 3.\n\nWhy others are wrong:\nOption 1 (YFANTAS) moves the last letter to the front instead of preserving the first letter.\nOption 2 (YSATNAF) completely reverses the entire string without anchoring the first letter.\nOption 4 (SATANF) alters the letter occurrences and drops the initial formatting rules.\n\nStudy tip:\nAlways test coding patterns on both provided samples to verify if anchoring, group splits, or partial reversals are consistently applied.

Correct answer (Option D):\nLet us trace the alphabetic and numeric operations between the paired terms:\n\nFirst cluster pair: AF 19 -> CH 16\n- A (+2) -> C\n- F (+2) -> H\n- 19 (-3) -> 16\n\nSecond cluster pair: GL 23 -> IN 20\n- G (+2) -> I\n- L (+2) -> N\n- 23 (-3) -> 20\n\nBoth pairs follow a uniform rule: the first character shifts by +2 positions, the second character shifts by +2 positions, and the number decreases by 3.\n\nApplying this exact logic to MR 36:\n- M (+2) -> O\n- R (+2) -> T\n- 36 (-3) -> 33\n\nCombining these modifications yields 'OT 33'. This matches Option D perfectly.\n\nWhy others are wrong:\nOption A (NT 33) applies an incorrect shift of only +1 to the first letter M.\nOption B (NR 34) miscalculates both the alphabetic changes and changes the numeric subtraction rule.\nOption C (OR 34) fails to add the correct shift value of +2 to the second letter R.\n\nStudy tip:\nWrite out positional ranks (e.g., M=13, R=18) when working out multi-variable analogies to quickly isolate individual shift parameters.

Correct answer (Option A):\nThe given expression is: 35 C 4 D 7 B 10 A 2 = ?\n\nFirst, substitute the operations according to the rules defined in the question stem:\n- Replace 'C' with '×'\n- Replace 'D' with '÷'\n- Replace 'B' with '-'\n- Replace 'A' with '+'\n\nThis gives the formatted equation:\n35 × 4 ÷ 7 - 10 + 2 = ?\n\nNow solve step-by-step following standard BODMAS conventions:\nStep 1 (Division): 4 ÷ 7 can be written as the fraction 4/7.\nExpression becomes: 35 × (4 / 7) - 10 + 2\nStep 2 (Multiplication): 35 × (4 / 7) = 5 × 4 = 20\nExpression simplifies to: 20 - 10 + 2\nStep 3 (Addition and Subtraction): \n20 - 10 = 10\n10 + 2 = 12\n\nThus, the final output is 12, which corresponds to Option A.\n\nWhy others are wrong:\nOption B (8) is incorrect due to a sign error during addition and subtraction steps.\nOption C (13) and Option D (10) arise from skipping the fraction properties of division before carrying out multiplication.\n\nStudy tip:\nWhen division results in a non-integer, group it with adjacent multiplication terms first as factors often cancel out smoothly.