SSC Junior Engineer Electrical — 2024 — 05 Jun 2024 — Official Paper — Kerala PSC PYQ Practice with Answers

Correct answer (Option A):\nLet us write down the letters of the word CLOSURE and arrange them in alphabetical order:\nOriginal: C L O S U R E\nSorted: C E L O R S U\n\nComparing the positions:\nC -> C (Unchanged)\nL -> E\nO -> L\nS -> O\nU -> R\nR -> S\nE -> U\n\nOnly the position of the letter 'C' remains unchanged. Thus, the count is exactly 1.\n\nWhy others are wrong:\nOptions B, C, and D are incorrect because tracking positions confirms that only one single letter keeps its original spot, not 2, 3, or 4.\n\nStudy tip:\nAlways list original and sorted indices vertically to avoid errors during comparison tests in SSC Reasoning alphabet series.

Correct answer (Option D):\nLet us map the letter shifts between the pairs:\n1) HGCA -> LKGE\nH (+4) -> L\nG (+4) -> K\nC (+4) -> G\nA (+4) -> E\n\n2) BKOM -> FOSQ\nB (+4) -> F\nK (+4) -> O\nO (+4) -> S\nM (+4) -> Q\n\nThe logical rule is a constant shift of +4 for each letter.\n\nApplying +4 to NSJD:\nN (+4) -> R\nS (+4) -> W\nJ (+4) -> N\nD (+4) -> H\nResult: RWNH\n\nWhy others are wrong:\nOptions A, B, and C do not match the required sequence transformation generated by shifting every single letter forward by 4 positions.\n\nStudy tip:\nQuickly writing positional numbers (N=14, S=19, J=10, D=4) makes calculating shifts (+4) fast and flawless.

Correct answer (Option C):\nLet's arrange the 6 people around a circle facing inwards based on the statements:\n1. M is to the immediate right of Q.\n2. Q is to the immediate right of O.\n3. L is to the immediate left of O.\n4. P is to the immediate left of L.\n\nCombining these constraints in order clockwise/counter-clockwise:\n- Put O down.\n- Q is to the immediate right of O, so order is O -> Q.\n- M is to the immediate right of Q, so order is O -> Q -> M.\n- L is to the immediate left of O, so layout becomes L -> O -> Q -> M.\n- P is to the immediate left of L, yielding P -> L -> O -> Q -> M.\n- Only N is left, which fills the remaining space between M and P. Thus, the full circular order moving clockwise is P -> L -> O -> Q -> M -> N.\n\nLooking at M, the person sitting to the immediate right of M is N.\n\nWhy others are wrong:\nOptions A, B, and D are incorrect because placing individuals according to the clear left/right boundary parameters leaves N explicitly to the right of M.\n\nStudy tip:\nWhen arranging seating facing the centre, clockwise corresponds to the left direction and counter-clockwise corresponds to the right direction.

Correct answer (Option D):\nLet us trace the series letter by letter position-wise:\nFirst letters: H (+2) -> J (+2) -> L (+2) -> N (+2) -> P\nSecond letters: N (+2) -> P (+2) -> R (+2) -> T (+2) -> V\nThird letters: L (+2) -> N (+2) -> P (+2) -> R (+2) -> T\n\nCombining the final letters yields the code string: PVT\n\nWhy others are wrong:\nOptions A, B, and C show scrambled order permutations or incorrect positional values that fail the steady +2 progression sequence rule.\n\nStudy tip:\nBreak down multi-letter combinations into standalone independent simple single-letter series tracks for quick alignment verification.

Correct answer (Option B):\nLet us trace Rahul's directional path step-by-step:\n1. Starts walking North (Facing North).\n2. Turns right -> Now facing East, walks 20 m.\n3. Turns right -> Now facing South, walks 10 m.\n4. Turns right -> Now facing West, walks 10 m.\n\nHis last movement path segment is towards the West direction. Therefore, he is currently headed West.\n\nWhy others are wrong:\nOptions A, C, and D are incorrect because turning right three successive times after initially heading North shifts the facing direction through East, South, and cleanly to West.