SSC JE Electrical — Paper II — 2024 — Official Paper — Kerala PSC PYQ Practice with Answers

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Paper 2JE2024English

Paper details

  • Paper code: ssc-je-electrical-paper-2-2024
  • Format: Full previous year paper — PYQ practice with answers

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Question 1 General Awareness
Which of the following pairs correctly defines the term in definition?
  1. A. Resultant Vector: The angular separation between two sinusoidal waveforms with the same frequency.
  2. B. Phasor Subtraction: The process of finding the vector difference between two phasors in a phasor diagram.
  3. C. Vector Subtraction: A single vector that represents the sum or difference of two or more vectors.
  4. D. Phase Difference: The representation of the complex amplitude and phase angle of a sinusoidal waveform.

Correct answer: B. Phasor Subtraction: The process of finding the vector difference between two phasors in a phasor diagram.

Correct answer (Option B):\nPhasor subtraction refers specifically to finding the vector difference between two time-varying sinusoidal quantities represented as phasors in a phasor diagram.\n\nWhy others are wrong:\nOption A defines Phase Difference rather than a Resultant Vector.\nOption C describes a Resultant Vector instead of Vector Subtraction.\nOption D describes a Phasor representation rather than a Phase Difference.\n\nStudy tip:\nPhasors represent both magnitude and phase angle of AC quantities at a fixed frequency, allowing complex AC circuit calculations to be performed using vector algebra.
Question 3 General Awareness
A 12-pole alternator running at a speed of 600 rpm will produce a frequency of:
  1. A. 40 Hz
  2. B. 30 Hz
  3. C. 60 Hz
  4. D. 50 Hz

Correct answer: C. 60 Hz

Correct answer (Option C):\nFormula: f = (P × N) / 120\nGiven: Poles (P) = 12, Speed (N) = 600 rpm\nStep 1: f = (12 × 600) / 120\nStep 2: f = 7200 / 120 = 60\nAnswer: 60 Hz.\n\nWhy others are wrong:\nOptions A, B, and D do not satisfy the standard synchronous frequency equation for the given parameters.\n\nStudy tip:\nAlternator frequency is directly proportional to both the number of field poles and the rotational speed of the rotor.
Question 4 General Awareness
The no-load primary input current lags the primary voltage by an angle:
  1. A. ϕ < 90°
  2. B. ϕ = 90°
  3. C. ϕ = 175°
  4. D. ϕ = 135°

Correct answer: A. ϕ < 90°

Correct answer (Option A):\nUnder no-load conditions, a transformer primary draws a small current consisting of core loss component (in phase with voltage) and magnetizing component (lagging voltage by 90°). The resultant current lags the voltage by a large angle, typically between 75° and 80°, which is strictly less than 90° (ϕ < 90°).\n\nWhy others are wrong:\nOption B is incorrect because active core losses prevent the current from lagging by a full 90°.\nOptions C and D describe angles greater than 90°, which would signify power delivery or unphysical reverse power flow.\n\nStudy tip:\nNo-load power factor is very low lagging because the magnetizing current component dominates the active loss component.
Question 5 General Awareness
Which of the given options best describes the truthfulness of the following statements with reference to the properties of the magnetic circuits?\nP: Permeance is the opposition offered to the magnetic flux by the magnetic path.\nQ: Magnetic lines of force cannot pass through air.
  1. A. Both P and Q are true
  2. B. P is true, but Q is false
  3. C. P is false, but Q is true
  4. D. Both P and Q are false

Correct answer: D. Both P and Q are false

Correct answer (Option D):\nStatement P is false because permeance is the reciprocal of reluctance; it represents the ease with which magnetic flux passes, not opposition. Statement Q is false because magnetic field lines can travel through any medium, including air or a vacuum.\n\nWhy others are wrong:\nOptions A, B, and C are incorrect because they falsely claim that P or Q is true.\n\nStudy tip:\nPermeance in a magnetic circuit is analogous to conductance in an electric circuit, while reluctance is analogous to resistance.
Question 6 General Awareness
For a series RLC circuit, at resonance the:
  1. A. current is maximum
  2. B. impedance is maximum
  3. C. power factor is zero
  4. D. current is minimum

Correct answer: A. current is maximum

Correct answer (Option A):\nIn a series RLC circuit at resonance, the inductive reactance cancels out the capacitive reactance (XL = XC). The net impedance drops to its minimum value equal to the circuit resistance (Z = R), causing the circuit current to reach its maximum peak value.\n\nWhy others are wrong:\nOption B is wrong because impedance is minimized at series resonance.\nOption C is wrong because the power factor is unity (1.0), not zero.\nOption D is wrong because current is maximized, not minimized.\n\nStudy tip:\nSeries resonance acts as a band-pass filter accepting maximum current at the resonant frequency, whereas parallel resonance minimizes current.

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